Что такое findslide.org?

FindSlide.org - это сайт презентаций, докладов, шаблонов в формате PowerPoint.


Для правообладателей

Обратная связь

Email: Нажмите что бы посмотреть 

Яндекс.Метрика

Презентация на тему Circles

The standard form of the equation of a circle with its center at the origin is Notice that both the x and y terms are squared. Linear equations don’t have either the x or y terms
CIRCLES The standard form of the equation of a circle with its center Let's look at the equationThe center of the circle is at the If the center of the circle is NOT at the origin then If you take the equation of a circle in standard form for If we'd have started with it like this, we'd have to complete Now let's work some examples:Find an equation of the circle with center Find an equation of the circle with center at (0, 0) that Find an equation of the circle with center at (-2, 5) and Find an equation of the circle with center at (8, 2) and Identify the center and radius and sketch the graph:To get in standard Identify the center and radius and sketch the graph:Remember the center values We have to complete the square on both the x's and y's Thank you for your attention!!!
Слайды презентации

Слайд 2
The standard form of the equation of a

The standard form of the equation of a circle with its

circle with its center at the origin is
Notice

that both the x and y terms are squared. Linear equations don’t have either the x or y terms squared. Parabolas have only the x term was squared (or only the y term, but NOT both).

r is the radius of the circle so if we take the square root of the right hand side, we'll know how big the radius is.


Слайд 3 Let's look at the equation
The center of the

Let's look at the equationThe center of the circle is at

circle is at the origin and the radius is

3. Let's graph this circle.

This is r2 so r = 3



Center at (0, 0)

Count out 3 in all directions since that is the radius







Слайд 4




If the center of the circle is NOT

If the center of the circle is NOT at the origin

at the origin then the equation for the standard

form of a circle looks like this:

The center of the circle is at (h, k).

The center of the circle is at (h, k) which is (3,1).

Find the center and radius and graph this circle.

The radius is 4

This is r2 so r = 4








Слайд 5 If you take the equation of a circle

If you take the equation of a circle in standard form

in standard form for example:
You can find the center

and radius easily. The center is at (-2, 4) and the radius is 2.

Remember center is at (h, k) with (x - h) and (y - k) since the x is plus something and not minus, (x + 2) can be written as (x - (-2))

This is r2 so r = 2

(x - (-2))

But what if it was not in standard form but multiplied out (FOILED)

Moving everything to one side in descending order and combining like terms we'd have:


Слайд 6 If we'd have started with it like this,

If we'd have started with it like this, we'd have to

we'd have to complete the square on both the

x's and y's to get in standard form.

Group x terms and a place to complete the square

Group y terms and a place to complete the square

Move constant to the other side

4

4

16

16

Write factored and wahlah! back in standard form.

Complete the square


Слайд 7 Now let's work some examples:
Find an equation of

Now let's work some examples:Find an equation of the circle with

the circle with center at (0, 0) and radius

7.

Let's sub in center and radius values in the standard form

0

0

7


Слайд 8 Find an equation of the circle with center

Find an equation of the circle with center at (0, 0)

at (0, 0) that passes through the point (-1,

-4).

The point (-1, -4) is on the circle so should work when we plug it in the equation:

Since the center is at (0, 0) we'll have

Subbing this in for r2 we have:


Слайд 9 Find an equation of the circle with center

Find an equation of the circle with center at (-2, 5)

at (-2, 5) and radius 6
Subbing in the values

in standard form we have:

-2

5

6


Слайд 10 Find an equation of the circle with center

Find an equation of the circle with center at (8, 2)

at (8, 2) and passes through the point (8,

0).

Subbing in the center values in standard form we have:

8

2

Since it passes through the point (8, 0) we can plug this point in for x and y to find r2.


Слайд 11 Identify the center and radius and sketch the

Identify the center and radius and sketch the graph:To get in

graph:
To get in standard form we don't want coefficients

on the squared terms so let's divide everything by 9.

So the center is at (0, 0) and the radius is 8/3.

9

9

9

Remember to square root this to get the radius.








Слайд 12 Identify the center and radius and sketch the

Identify the center and radius and sketch the graph:Remember the center

graph:
Remember the center values end up being the opposite

sign of what is with the x and y and the right hand side is the radius squared.

So the center is at (-4, 3) and the radius is 5.








Слайд 13 We have to complete the square on both

We have to complete the square on both the x's and

the x's and y's to get in standard form.
Group

x terms and a place to complete the square

Group y terms and a place to complete the square

Move constant to the other side

9

9

4

4

Write factored for standard form.

Find the center and radius of the circle:

So the center is at (-3, 2) and the radius is 4.


  • Имя файла: circles.pptx
  • Количество просмотров: 90
  • Количество скачиваний: 0